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(D) is $o$-hydroxybenzoic acid (salicylic acid),which exhibits intramolecular $H$-bonding.$(B)$ is $p$-hydroxybenzoic acid,which exhibits intermolecul

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$(a)$,$(b)$ and $(c)$ are true

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(D) is $o$-hydroxybenzoic acid (salicylic acid),which exhibits intramolecular $H$-bonding.$(B)$ is $p$-hydroxybenzoic acid,which exhibits intermolecular $H$-bonding.$(a)$ Due to intermolecular $H$-bonding,$(B)$ molecules associate to form a lattice structure,making it more likely to be crystalline than $(A)$,which exists as discrete molecules due to intramolecular $H$-bonding. Thus,$(a)$ is true.$(b)$ Intermolecular $H$-bonding in $(B)$ leads to higher molecular association,requiring more energy to break,thus $(B)$ has a higher boiling point than $(A)$. Thus,$(b)$ is true.$(c)$ $(B)$ can form more extensive $H$-bonding with water molecules compared to $(A)$ due to the availability of its functional groups,making it more soluble in water. Thus,$(c)$ is true.Therefore,all three statements are correct.

Consider the following molecules and statements related to them:
$(a)$ $(B)$ is more likely to be crystalline than $(A)$
$(b)$ $(B)$ has a higher boiling point than $(A)$
$(c)$ $(B)$ dissolves more readily than $(A)$ in water.
Identify the correct option from below:

Similar Questions

What are $X$ and $Y$ respectively in the following reaction sequence?
Styrene $\xrightarrow[(ii) H_3O^+]{(i) KMnO_4 / KOH} X$ $\xrightarrow{Br_2 / FeBr_3} Y$

Oxalic acid on being heated up to $90^\circ C$ with conc. $H_2SO_4$ forms:

Identify the major product from the following reaction sequence:
$Cyclohexyl-CH_2CH_2OH \xrightarrow[(ii) Cl_2/Red \ P \ (iii) H_2O]{(i) CrO_3, H_2SO_4}$

Which of the following is most acidic?

Identify the reaction which will $NOT$ produce an alcohol as a major product.

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Consider the following molecules and statements related to them:$(a)$ $(B)$ is more likely to be crystalline than $(A)$$(b)$ $(B)$ has a higher boiling point than $(A)$$(c)$ $(B)$ dissolves more readily than $(A)$ in water.Identify the correct option from below: